y=(40+.05(y-10))+50+315

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Solution for y=(40+.05(y-10))+50+315 equation: 



y=(40+.05(y-10))+50+315

We move all terms to the left:

y-((40+.05(y-10))+50+315)=0



We calculate terms in parentheses: -((40+.05(y-10))+50+315), so:

(40+.05(y-10))+50+315

We add all the numbers together, and all the variables

(40+.05(y-10))+365



We calculate terms in parentheses: +(40+.05(y-10)), so:

40+.05(y-10)

determiningTheFunctionDomain
.05(y-10)+40

We multiply parentheses

0.05y-0.5+40

We add all the numbers together, and all the variables

0.05y+39.5

Back to the equation:

+(0.05y+39.5)



We get rid of parentheses

0.05y+39.5+365

We add all the numbers together, and all the variables

0.05y+404.5

Back to the equation:

-(0.05y+404.5)



We get rid of parentheses

y-0.05y-404.5=0

We add all the numbers together, and all the variables

0.95y-404.5=0

We move all terms containing y to the left, all other terms to the right

0.95y=404.5

y=404.5/0.95

y=425+0.75/0.95

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