y=(40+0.5(y-10))+50+315

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Solution for y=(40+0.5(y-10))+50+315 equation: 



y=(40+0.5(y-10))+50+315

We move all terms to the left:

y-((40+0.5(y-10))+50+315)=0



We calculate terms in parentheses: -((40+0.5(y-10))+50+315), so:

(40+0.5(y-10))+50+315

We add all the numbers together, and all the variables

(40+0.5(y-10))+365



We calculate terms in parentheses: +(40+0.5(y-10)), so:

40+0.5(y-10)

determiningTheFunctionDomain
0.5(y-10)+40

We multiply parentheses

0.5y-5+40

We add all the numbers together, and all the variables

0.5y+35

Back to the equation:

+(0.5y+35)



We get rid of parentheses

0.5y+35+365

We add all the numbers together, and all the variables

0.5y+400

Back to the equation:

-(0.5y+400)



We get rid of parentheses

y-0.5y-400=0

We add all the numbers together, and all the variables

0.5y-400=0

We move all terms containing y to the left, all other terms to the right

0.5y=400

y=400/0.5

y=800

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