y=(4x)/(1+x)

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Solution for y=(4x)/(1+x) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

y = (4*x)/(x+1) // - (4*x)/(x+1)

y-((4*x)/(x+1)) = 0

y-4*x*(x+1)^-1 = 0

(-4*x)/(x+1)+y = 0

(-4*x)/(x+1)+(y*(x+1))/(x+1) = 0

y*(x+1)-4*x = 0

x*y-4*x+y = 0

x*y-4*x+y = 0

x*y+y = 0 // - y

x*y = -y // : y

x = -y/y

x = -1

x+1 = 0

(x+1)/(x+1) = 0

(x+1)/(x+1) = 0 // * x+1

x+1 = 0

x+1 = 0 // - 1

x = -1

x in { -1} 

x belongs to the empty set

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