y=(6n+4)n=5

Solution for y=(6n+4)n=5 equation:

=(6Y+4)Y=5

We move all terms to the left:

-((6Y+4)Y)=0


We calculate terms in parentheses: -((6Y+4)Y), so:

(6Y+4)Y

We multiply parentheses

6Y^2+4Y

Back to the equation:

-(6Y^2+4Y)


We get rid of parentheses

-6Y^2-4Y=0

a = -6; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-6)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-6}=\frac{0}{-12}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-6}=\frac{8}{-12}
=-2/3
$