y=(abs(ln(x+2))-2)

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Solution for y=(abs(ln(x+2))-2) equation: 


Simplifying
y = (abs(ln(x + 2)) + -2)

Reorder the terms:
y = (abs(ln(2 + x)) + -2)
y = (abs((2 * ln + x * ln)) + -2)
y = (abs((2ln + lnx)) + -2)
y = ((2ln * abs + lnx * abs) + -2)
y = ((2ablns + ablnsx) + -2)

Reorder the terms:
y = (-2 + 2ablns + ablnsx)

Remove parenthesis around (-2 + 2ablns + ablnsx)
y = -2 + 2ablns + ablnsx

Solving
y = -2 + 2ablns + ablnsx

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -2 + 2ablns + ablnsx

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