y=(x+1)/(2x+1)

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Solution for y=(x+1)/(2x+1) equation: 


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

y = (x+1)/(2*x+1) // - (x+1)/(2*x+1)

y-((x+1)/(2*x+1)) = 0

(-1*(x+1))/(2*x+1)+y = 0

(-1*(x+1))/(2*x+1)+(y*(2*x+1))/(2*x+1) = 0

y*(2*x+1)-1*(x+1) = 0

2*x*y-x+y-1 = 0

(2*x*y-x+y-1)/(2*x+1) = 0

(2*x*y-x+y-1)/(2*x+1) = 0 // * 2*x+1

2*x*y-x+y-1 = 0

2*x*y+y-1 = 0 // - y-1

2*x*y = -(y-1) // : 2*y

x = (-(y-1))/(2*y)

x = (1-y)/(2*y)

x = (1-y)/(2*y)

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