y=-1+2(3(-2)-2)

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Solution for y=-1+2(3(-2)-2) equation: 



y=-1+2(3(-2)-2)

We move all terms to the left:

y-(-1+2(3(-2)-2))=0

We add all the numbers together, and all the variables

y+17=0

We move all terms containing y to the left, all other terms to the right

y=-17

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