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y=-16y^2+64y+80
We move all terms to the left:
y-(-16y^2+64y+80)=0
We get rid of parentheses
16y^2-64y+y-80=0
We add all the numbers together, and all the variables
16y^2-63y-80=0
a = 16; b = -63; c = -80;
Δ = b2-4ac
Δ = -632-4·16·(-80)
Δ = 9089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{9089}}{2*16}=\frac{63-\sqrt{9089}}{32} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{9089}}{2*16}=\frac{63+\sqrt{9089}}{32} $
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