y=-2x0-1/2

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Solution for y=-2x0-1/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y = -2*x^0-(1/2) // + -2*x^0-(1/2)

y-(-2*x^0)+1/2 = 0

y+1/2+2 = 0

y+5/2 = 0

x należy do R

x in (-oo:0) U (0:+oo)

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