y=-3(6-y)+10

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Solution for y=-3(6-y)+10 equation:



y=-3(6-y)+10
We move all terms to the left:
y-(-3(6-y)+10)=0
We add all the numbers together, and all the variables
y-(-3(-1y+6)+10)=0
We calculate terms in parentheses: -(-3(-1y+6)+10), so:
-3(-1y+6)+10
We multiply parentheses
3y-18+10
We add all the numbers together, and all the variables
3y-8
Back to the equation:
-(3y-8)
We get rid of parentheses
y-3y+8=0
We add all the numbers together, and all the variables
-2y+8=0
We move all terms containing y to the left, all other terms to the right
-2y=-8
y=-8/-2
y=+4

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