y=0.05y(1-y)

Solution for y=0.05y(1-y) equation:

y=0.05y(1-y)

We move all terms to the left:

y-(0.05y(1-y))=0

We add all the numbers together, and all the variables

y-(0.05y(-1y+1))=0


We calculate terms in parentheses: -(0.05y(-1y+1)), so:

0.05y(-1y+1)

We multiply parentheses

0y^2+0y

We add all the numbers together, and all the variables

y^2+y

Back to the equation:

-(y^2+y)


We get rid of parentheses

-y^2+y-y=0

We add all the numbers together, and all the variables

-1y^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-2}=0$