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y=1+2(4/5)
We move all terms to the left:
y-(1+2(4/5))=0
We add all the numbers together, and all the variables
y-(1+2(+4/5))=0
We multiply all the terms by the denominator
y*5))-(1+2(+4=0
Wy multiply elements
5y^2+4=0
a = 5; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·5·4
Δ = -80
Delta is less than zero, so there is no solution for the equation
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