y=1/2(x2-3)

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Solution for y=1/2(x2-3) equation: 


x in (-oo:+oo)

y = (1/2)*(x^2-3) // - (1/2)*(x^2-3)

y-((1/2)*(x^2-3)) = 0

(-1/2)*(x^2-3)+y = 0

y-1/2*(x^2-3) = 0

y-1/2*(x^2-3) = 0

y-1/2*x^2+3/2 = 0

y-1/2*x^2+3/2 = 0

-1/2*x^2 = -(y+3/2) // : -1/2

x^2 = 2*(y+3/2)

x^2 = 2*(y+3/2) // ^ 1/2

abs(x) = 2^(1/2)*(y+3/2)^(1/2)

x = 2^(1/2)*(y+3/2)^(1/2) or x = -(2^(1/2)*(y+3/2)^(1/2))

x in { 2^(1/2)*(y+3/2)^(1/2), -(2^(1/2)*(y+3/2)^(1/2)) }

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