If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
y = (1/2)*d^1*d^2 // - (1/2)*d^1*d^2
y-((1/2)*d^1*d^2) = 0
(-1/2)*d^3+y = 0
y-1/2*d^3 = 0
x należy do R
x in (-oo:+oo)
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