y=10+2z;y+58-6z

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Solution for y=10+2z;y+58-6z system of equations: 


  • /| y-(2*z)-10 = 0| y-(6*z)+58 = 0
  • We try to solve the equation: y-(2*z)-10 = 0
  • y-2*z-10 = 0 // - y-10
  • -2*z = -(y-10) // : -2
  • z = (-(y-10))/(-2)
  • z = (10-y)/(-2)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| y-(6*((10-y)/(-2)))+58 = 0| z = (10-y)/(-2)
  • (-1*6*(10-y))/(-2)+y+58 = 0
  • 30-2*y+58 = 0
  • 88-2*y = 0
  • 88-2*y = 0 // - 88
  • -2*y = -88 // : -2
  • y = -88/(-2)
  • y = 44
  • We insert the solution into one of the initial equations of our system of equations
  • For z = (10-y)/(-2): 
  • z = (10-44)/(-2)
  • z = -34/(-2)
  • z = 17
  • We get a system of equations:
  • /| z = 17| y = 44

 

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