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y=2(-12/11)+4
We move all terms to the left:
y-(2(-12/11)+4)=0
We multiply all the terms by the denominator
y*11)+4)-(2(-12=0
Wy multiply elements
11y^2-12=0
a = 11; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·11·(-12)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{33}}{2*11}=\frac{0-4\sqrt{33}}{22} =-\frac{4\sqrt{33}}{22} =-\frac{2\sqrt{33}}{11} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{33}}{2*11}=\frac{0+4\sqrt{33}}{22} =\frac{4\sqrt{33}}{22} =\frac{2\sqrt{33}}{11} $
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