y=2(-7/5)-2

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Solution for y=2(-7/5)-2 equation:



y=2(-7/5)-2
We move all terms to the left:
y-(2(-7/5)-2)=0
We multiply all the terms by the denominator
y*5)-2)-(2(-7=0
Wy multiply elements
5y^2-7=0
a = 5; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·5·(-7)
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{35}}{2*5}=\frac{0-2\sqrt{35}}{10} =-\frac{2\sqrt{35}}{10} =-\frac{\sqrt{35}}{5} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{35}}{2*5}=\frac{0+2\sqrt{35}}{10} =\frac{2\sqrt{35}}{10} =\frac{\sqrt{35}}{5} $

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