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y=23+3y^2
We move all terms to the left:
y-(23+3y^2)=0
We get rid of parentheses
-3y^2+y-23=0
a = -3; b = 1; c = -23;
Δ = b2-4ac
Δ = 12-4·(-3)·(-23)
Δ = -275
Delta is less than zero, so there is no solution for the equation
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