y=3(-1)-19/5

Solution for y=3(-1)-19/5 equation:

y=3(-1)-19/5

We move all terms to the left:

y-(3(-1)-19/5)=0

We multiply all the terms by the denominator


y*5)-(3(-1)-19=0

Wy multiply elements

5y^2-19=0

a = 5; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·5·(-19)
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{95}}{2*5}=\frac{0-2\sqrt{95}}{10}
=-\frac{2\sqrt{95}}{10}
=-\frac{\sqrt{95}}{5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{95}}{2*5}=\frac{0+2\sqrt{95}}{10}
=\frac{2\sqrt{95}}{10}
=\frac{\sqrt{95}}{5}
$