y=3(-8/10y)-3

Solution for y=3(-8/10y)-3 equation:

y=3(-8/10y)-3

We move all terms to the left:

y-(3(-8/10y)-3)=0


Domain of the equation: 10y)-3)!=0

y!=0/1

y!=0

y∈R


We multiply all the terms by the denominator


y*10y)-3)-(3(-8=0

Wy multiply elements

10y^2-8=0

a = 10; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·10·(-8)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*10}=\frac{0-8\sqrt{5}}{20}
=-\frac{8\sqrt{5}}{20}
=-\frac{2\sqrt{5}}{5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*10}=\frac{0+8\sqrt{5}}{20}
=\frac{8\sqrt{5}}{20}
=\frac{2\sqrt{5}}{5}
$