y=3/2x-3/2+3

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Solution for y=3/2x-3/2+3 equation: 


x in (-oo:+oo)

y = (3/2)*x-(3/2)+3 // - (3/2)*x-(3/2)+3

y-((3/2)*x)+3/2-3 = 0

(-3/2)*x+y+3/2-3 = 0

y-3/2*x-3/2 = 0 // - y-3/2

-3/2*x = -(y-3/2) // : -3/2

x = (-(y-3/2))/(-3/2)

x = -2/3*(3/2-y)

x = -2/3*(3/2-y)

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