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y=3/4y-6
We move all terms to the left:
y-(3/4y-6)=0
Domain of the equation: 4y-6)!=0We get rid of parentheses
y∈R
y-3/4y+6=0
We multiply all the terms by the denominator
y*4y+6*4y-3=0
Wy multiply elements
4y^2+24y-3=0
a = 4; b = 24; c = -3;
Δ = b2-4ac
Δ = 242-4·4·(-3)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*4}=\frac{-24-4\sqrt{39}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*4}=\frac{-24+4\sqrt{39}}{8} $
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