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y=3/y-2
We move all terms to the left:
y-(3/y-2)=0
Domain of the equation: y-2)!=0We get rid of parentheses
y∈R
y-3/y+2=0
We multiply all the terms by the denominator
y*y+2*y-3=0
We add all the numbers together, and all the variables
2y+y*y-3=0
Wy multiply elements
y^2+2y-3=0
a = 1; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·1·(-3)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*1}=\frac{-6}{2} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*1}=\frac{2}{2} =1 $
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