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y=32(y-6/4)+10
We move all terms to the left:
y-(32(y-6/4)+10)=0
We add all the numbers together, and all the variables
y-(32(+y-6/4)+10)=0
We multiply all the terms by the denominator
y*4)+10)-(32(+y-6=0
We add all the numbers together, and all the variables
y+y*4)+10)-(32(-6=0
Wy multiply elements
4y^2+y-6=0
a = 4; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·4·(-6)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*4}=\frac{-1-\sqrt{97}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*4}=\frac{-1+\sqrt{97}}{8} $
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