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y=4(2/3y)+50
We move all terms to the left:
y-(4(2/3y)+50)=0
Domain of the equation: 3y)+50)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
y-(4(+2/3y)+50)=0
We multiply all the terms by the denominator
y*3y)+50)-(4(+2=0
Wy multiply elements
3y^2+2=0
a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation
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