y=4(3+y)-y=6+3(y+2)

Solution for y=4(3+y)-y=6+3(y+2) equation:

y=4(3+y)-y=6+3(y+2)

We move all terms to the left:

y-(4(3+y)-y)=0

We add all the numbers together, and all the variables

y-(4(y+3)-y)=0


We calculate terms in parentheses: -(4(y+3)-y), so:

4(y+3)-y

We add all the numbers together, and all the variables

-1y+4(y+3)

We multiply parentheses

-1y+4y+12

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)


We get rid of parentheses

y-3y-12=0

We add all the numbers together, and all the variables

-2y-12=0

We move all terms containing y to the left, all other terms to the right

-2y=12

y=12/-2

y=-6