y=4/5y-1

Solution for y=4/5y-1 equation:

y=4/5y-1

We move all terms to the left:

y-(4/5y-1)=0


Domain of the equation: 5y-1)!=0

y∈R


We get rid of parentheses

y-4/5y+1=0

We multiply all the terms by the denominator


y*5y+1*5y-4=0

Wy multiply elements

5y^2+5y-4=0

a = 5; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·5·(-4)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{105}}{2*5}=\frac{-5-\sqrt{105}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{105}}{2*5}=\frac{-5+\sqrt{105}}{10}
$