y=5,12+4(y+3)=

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Solution for y=5,12+4(y+3)= equation: 



y=5.12+4(y+3)=

We move all terms to the left:

y-(5.12+4(y+3))=0



We calculate terms in parentheses: -(5.12+4(y+3)), so:

5.12+4(y+3)

determiningTheFunctionDomain
4(y+3)+5.12

We multiply parentheses

4y+12+5.12

We add all the numbers together, and all the variables

4y+17.12

Back to the equation:

-(4y+17.12)



We get rid of parentheses

y-4y-17.12=0

We add all the numbers together, and all the variables

-3y-17.12=0

We move all terms containing y to the left, all other terms to the right

-3y=17.12

y=17.12/-3

y=-5+2.12/3

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