y=6(2y-1)+3(3y+2)

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Solution for y=6(2y-1)+3(3y+2) equation: 



y=6(2y-1)+3(3y+2)

We move all terms to the left:

y-(6(2y-1)+3(3y+2))=0



We calculate terms in parentheses: -(6(2y-1)+3(3y+2)), so:

6(2y-1)+3(3y+2)

We multiply parentheses

12y+9y-6+6

We add all the numbers together, and all the variables

21y

Back to the equation:

-(21y)



We add all the numbers together, and all the variables

-20y=0

y=0/-20

y=0

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