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=6Y^2+5Y+3
We move all terms to the left:
-(6Y^2+5Y+3)=0
We get rid of parentheses
-6Y^2-5Y-3=0
a = -6; b = -5; c = -3;
Δ = b2-4ac
Δ = -52-4·(-6)·(-3)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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