y=8-3y/y-4

Solution for y=8-3y/y-4 equation:

y=8-3y/y-4

We move all terms to the left:

y-(8-3y/y-4)=0


Domain of the equation: y-4)!=0

y∈R


We add all the numbers together, and all the variables

y-(-3y/y+4)=0

We get rid of parentheses

y+3y/y-4=0

We multiply all the terms by the denominator


y*y+3y-4*y=0

We add all the numbers together, and all the variables

-1y+y*y=0

Wy multiply elements

y^2-1y=0

a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2}
=1
$