y=8-3y/y-4

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Solution for y=8-3y/y-4 equation:



y=8-3y/y-4
We move all terms to the left:
y-(8-3y/y-4)=0
Domain of the equation: y-4)!=0
y∈R
We add all the numbers together, and all the variables
y-(-3y/y+4)=0
We get rid of parentheses
y+3y/y-4=0
We multiply all the terms by the denominator
y*y+3y-4*y=0
We add all the numbers together, and all the variables
-1y+y*y=0
Wy multiply elements
y^2-1y=0
a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2} =0 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2} =1 $

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