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y=8-3y/y-4
We move all terms to the left:
y-(8-3y/y-4)=0
Domain of the equation: y-4)!=0We add all the numbers together, and all the variables
y∈R
y-(-3y/y+4)=0
We get rid of parentheses
y+3y/y-4=0
We multiply all the terms by the denominator
y*y+3y-4*y=0
We add all the numbers together, and all the variables
-1y+y*y=0
Wy multiply elements
y^2-1y=0
a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2} =1 $
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