z(3-5z)=1

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Solution for z(3-5z)=1 equation: 



z(3-5z)=1

We move all terms to the left:

z(3-5z)-(1)=0

We add all the numbers together, and all the variables

z(-5z+3)-1=0

We multiply parentheses

-5z^2+3z-1=0

a = -5; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·(-5)·(-1)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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