z(n-3)=4n+1

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Solution for z(n-3)=4n+1 equation:


Simplifying
z(n + -3) = 4n + 1

Reorder the terms:
z(-3 + n) = 4n + 1
(-3 * z + n * z) = 4n + 1

Reorder the terms:
(nz + -3z) = 4n + 1
(nz + -3z) = 4n + 1

Reorder the terms:
nz + -3z = 1 + 4n

Solving
nz + -3z = 1 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
nz + -4n + -3z = 1 + 4n + -4n

Reorder the terms:
-4n + nz + -3z = 1 + 4n + -4n

Combine like terms: 4n + -4n = 0
-4n + nz + -3z = 1 + 0
-4n + nz + -3z = 1

Add '3z' to each side of the equation.
-4n + nz + -3z + 3z = 1 + 3z

Combine like terms: -3z + 3z = 0
-4n + nz + 0 = 1 + 3z
-4n + nz = 1 + 3z

Reorder the terms:
-1 + -4n + nz + -3z = 1 + 3z + -1 + -3z

Reorder the terms:
-1 + -4n + nz + -3z = 1 + -1 + 3z + -3z

Combine like terms: 1 + -1 = 0
-1 + -4n + nz + -3z = 0 + 3z + -3z
-1 + -4n + nz + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
-1 + -4n + nz + -3z = 0

The solution to this equation could not be determined.

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