z(z+1)=3+2i

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Solution for z(z+1)=3+2i equation:


Simplifying
z(z + 1) = 3 + 2i

Reorder the terms:
z(1 + z) = 3 + 2i
(1 * z + z * z) = 3 + 2i
(1z + z2) = 3 + 2i

Solving
1z + z2 = 3 + 2i

Solving for variable 'z'.

Reorder the terms:
-3 + -2i + 1z + z2 = 3 + 2i + -3 + -2i

Reorder the terms:
-3 + -2i + 1z + z2 = 3 + -3 + 2i + -2i

Combine like terms: 3 + -3 = 0
-3 + -2i + 1z + z2 = 0 + 2i + -2i
-3 + -2i + 1z + z2 = 2i + -2i

Combine like terms: 2i + -2i = 0
-3 + -2i + 1z + z2 = 0

The solution to this equation could not be determined.

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