z(z+2)=(z*z)+2z+1

Solution for z(z+2)=(z*z)+2z+1 equation:

Simplifying
z(z + 2) = (z * z) + 2z + 1

Reorder the terms:
z(2 + z) = (z * z) + 2z + 1
(2 * z + z * z) = (z * z) + 2z + 1
(2z + z2) = (z * z) + 2z + 1

Multiply z * z
2z + z2 = (z2) + 2z + 1
2z + z2 = z2 + 2z + 1

Reorder the terms:
2z + z2 = 1 + 2z + z2

Add '-2z' to each side of the equation.
2z + -2z + z2 = 1 + 2z + -2z + z2

Combine like terms: 2z + -2z = 0
0 + z2 = 1 + 2z + -2z + z2
z2 = 1 + 2z + -2z + z2

Combine like terms: 2z + -2z = 0
z2 = 1 + 0 + z2
z2 = 1 + z2

Add '-1z2' to each side of the equation.
z2 + -1z2 = 1 + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
0 = 1 + z2 + -1z2

Combine like terms: z2 + -1z2 = 0
0 = 1 + 0
0 = 1

Solving
0 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.