z(z+2)=35

Solution for z(z+2)=35 equation:

Simplifying
z(z + 2) = 35

Reorder the terms:
z(2 + z) = 35
(2 * z + z * z) = 35
(2z + z2) = 35

Solving
2z + z2 = 35

Solving for variable 'z'.

Reorder the terms:
-35 + 2z + z2 = 35 + -35

Combine like terms: 35 + -35 = 0
-35 + 2z + z2 = 0

Factor a trinomial.
(-7 + -1z)(5 + -1z) = 0

Subproblem 1
Set the factor '(-7 + -1z)' equal to zero and attempt to solve:

Simplifying
-7 + -1z = 0

Solving
-7 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1z = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1z = 0 + 7
-1z = 0 + 7

Combine like terms: 0 + 7 = 7
-1z = 7

Divide each side by '-1'.
z = -7

Simplifying
z = -7
Subproblem 2
Set the factor '(5 + -1z)' equal to zero and attempt to solve:

Simplifying
5 + -1z = 0

Solving
5 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1z = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1z = 0 + -5
-1z = 0 + -5

Combine like terms: 0 + -5 = -5
-1z = -5

Divide each side by '-1'.
z = 5

Simplifying
z = 5
Solution
z = {-7, 5}