z+(z+1)+(z+2)=-36

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Solution for z+(z+1)+(z+2)=-36 equation:



z+(z+1)+(z+2)=-36
We move all terms to the left:
z+(z+1)+(z+2)-(-36)=0
We add all the numbers together, and all the variables
z+(z+1)+(z+2)+36=0
We get rid of parentheses
z+z+z+1+2+36=0
We add all the numbers together, and all the variables
3z+39=0
We move all terms containing z to the left, all other terms to the right
3z=-39
z=-39/3
z=-13

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