z+1+z+18=z+50

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Solution for z+1+z+18=z+50 equation: 



z+1+z+18=z+50

We move all terms to the left:

z+1+z+18-(z+50)=0

We add all the numbers together, and all the variables

2z-(z+50)+19=0

We get rid of parentheses

2z-z-50+19=0

We add all the numbers together, and all the variables

z-31=0

We move all terms containing z to the left, all other terms to the right

z=31

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