z+12=4z

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Solution for z+12=4z equation: 



z+12=4z

We move all terms to the left:

z+12-(4z)=0

We add all the numbers together, and all the variables

-3z+12=0

We move all terms containing z to the left, all other terms to the right

-3z=-12

z=-12/-3

z=+4

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