z+16+(72/z)=0

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Solution for z+16+(72/z)=0 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z+72/z+16 = 0

1*z^1+72*z^-1+16*z^0 = 0

(1*z^2+16*z^1+72*z^0)/(z^1) = 0 // * z^2

z^1*(1*z^2+16*z^1+72*z^0) = 0

z^1

z^2+16*z+72 = 0

z^2+16*z+72 = 0

DELTA = 16^2-(1*4*72)

DELTA = -32

DELTA < 0

z in { } 

z belongs to the empty set

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