z+2(4+z)=3z+8

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Solution for z+2(4+z)=3z+8 equation:


Simplifying
z + 2(4 + z) = 3z + 8
z + (4 * 2 + z * 2) = 3z + 8
z + (8 + 2z) = 3z + 8

Reorder the terms:
8 + z + 2z = 3z + 8

Combine like terms: z + 2z = 3z
8 + 3z = 3z + 8

Reorder the terms:
8 + 3z = 8 + 3z

Add '-8' to each side of the equation.
8 + -8 + 3z = 8 + -8 + 3z

Combine like terms: 8 + -8 = 0
0 + 3z = 8 + -8 + 3z
3z = 8 + -8 + 3z

Combine like terms: 8 + -8 = 0
3z = 0 + 3z
3z = 3z

Add '-3z' to each side of the equation.
3z + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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