z+2(z+3)=5(2z-3)

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Solution for z+2(z+3)=5(2z-3) equation: 



z+2(z+3)=5(2z-3)

We move all terms to the left:

z+2(z+3)-(5(2z-3))=0

We multiply parentheses

z+2z-(5(2z-3))+6=0



We calculate terms in parentheses: -(5(2z-3)), so:

5(2z-3)

We multiply parentheses

10z-15

Back to the equation:

-(10z-15)



We add all the numbers together, and all the variables

3z-(10z-15)+6=0

We get rid of parentheses

3z-10z+15+6=0

We add all the numbers together, and all the variables

-7z+21=0

We move all terms containing z to the left, all other terms to the right

-7z=-21

z=-21/-7

z=+3

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