z+2(z-3)+(z/2)=29

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Solution for z+2(z-3)+(z/2)=29 equation:



z+2(z-3)+(z/2)=29
We move all terms to the left:
z+2(z-3)+(z/2)-(29)=0
We add all the numbers together, and all the variables
z+2(z-3)+(+z/2)-29=0
We multiply parentheses
z+2z+(+z/2)-6-29=0
We get rid of parentheses
z+2z+z/2-6-29=0
We multiply all the terms by the denominator
z*2+2z*2+z-6*2-29*2=0
We add all the numbers together, and all the variables
z+z*2+2z*2-70=0
Wy multiply elements
z+2z+4z-70=0
We add all the numbers together, and all the variables
7z-70=0
We move all terms containing z to the left, all other terms to the right
7z=70
z=70/7
z=10

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