z+2(z-3)+(z/2)=29

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Solution for z+2(z-3)+(z/2)=29 equation: 



z+2(z-3)+(z/2)=29

We move all terms to the left:

z+2(z-3)+(z/2)-(29)=0

We add all the numbers together, and all the variables

z+2(z-3)+(+z/2)-29=0

We multiply parentheses

z+2z+(+z/2)-6-29=0

We get rid of parentheses

z+2z+z/2-6-29=0

We multiply all the terms by the denominator


z*2+2z*2+z-6*2-29*2=0

We add all the numbers together, and all the variables

z+z*2+2z*2-70=0

Wy multiply elements

z+2z+4z-70=0

We add all the numbers together, and all the variables

7z-70=0

We move all terms containing z to the left, all other terms to the right

7z=70

z=70/7

z=10

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