z+2/z-3=5/-3

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Solution for z+2/z-3=5/-3 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z+2/z-3 = 5/(-3) // - 5/(-3)

z+2/z-(5/(-3))-3 = 0

z+2/z+5/3-3 = 0

1*z^1+2*z^-1-4/3*z^0 = 0

(1*z^2-4/3*z^1+2*z^0)/(z^1) = 0 // * z^2

z^1*(1*z^2-4/3*z^1+2*z^0) = 0

z^1

z^2+(-4/3)*z+2 = 0

z^2+(-4/3)*z+2 = 0

DELTA = (-4/3)^2-(1*2*4)

DELTA = -56/9

DELTA < 0

z in { } 

z belongs to the empty set

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