z+2=(-z)+2

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Solution for z+2=(-z)+2 equation: 



z+2=(-z)+2

We move all terms to the left:

z+2-((-z)+2)=0

We add all the numbers together, and all the variables

z-((-1z)+2)+2=0



We calculate terms in parentheses: -((-1z)+2), so:

(-1z)+2

We get rid of parentheses

-1z+2

Back to the equation:

-(-1z+2)



We get rid of parentheses

z+1z-2+2=0

We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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