z+3(2+4z)=6(z+1)+5z

Solution for z+3(2+4z)=6(z+1)+5z equation:

Simplifying
z + 3(2 + 4z) = 6(z + 1) + 5z
z + (2 * 3 + 4z * 3) = 6(z + 1) + 5z
z + (6 + 12z) = 6(z + 1) + 5z

Reorder the terms:
6 + z + 12z = 6(z + 1) + 5z

Combine like terms: z + 12z = 13z
6 + 13z = 6(z + 1) + 5z

Reorder the terms:
6 + 13z = 6(1 + z) + 5z
6 + 13z = (1 * 6 + z * 6) + 5z
6 + 13z = (6 + 6z) + 5z

Combine like terms: 6z + 5z = 11z
6 + 13z = 6 + 11z

Add '-6' to each side of the equation.
6 + -6 + 13z = 6 + -6 + 11z

Combine like terms: 6 + -6 = 0
0 + 13z = 6 + -6 + 11z
13z = 6 + -6 + 11z

Combine like terms: 6 + -6 = 0
13z = 0 + 11z
13z = 11z

Solving
13z = 11z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-11z' to each side of the equation.
13z + -11z = 11z + -11z

Combine like terms: 13z + -11z = 2z
2z = 11z + -11z

Combine like terms: 11z + -11z = 0
2z = 0

Divide each side by '2'.
z = 0

Simplifying
z = 0