z+3(2-i)=5+i

Solution for z+3(2-i)=5+i equation:

Simplifying
z + 3(2 + -1i) = 5 + i
z + (2 * 3 + -1i * 3) = 5 + i
z + (6 + -3i) = 5 + i

Reorder the terms:
6 + -3i + z = 5 + i

Solving
6 + -3i + z = 5 + i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
6 + -3i + -1i + z = 5 + i + -1i

Combine like terms: -3i + -1i = -4i
6 + -4i + z = 5 + i + -1i

Combine like terms: i + -1i = 0
6 + -4i + z = 5 + 0
6 + -4i + z = 5

Add '-6' to each side of the equation.
6 + -4i + -6 + z = 5 + -6

Reorder the terms:
6 + -6 + -4i + z = 5 + -6

Combine like terms: 6 + -6 = 0
0 + -4i + z = 5 + -6
-4i + z = 5 + -6

Combine like terms: 5 + -6 = -1
-4i + z = -1

Add '-1z' to each side of the equation.
-4i + z + -1z = -1 + -1z

Combine like terms: z + -1z = 0
-4i + 0 = -1 + -1z
-4i = -1 + -1z

Divide each side by '-4'.
i = 0.25 + 0.25z

Simplifying
i = 0.25 + 0.25z