z+3(z+2)=14+2z

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Solution for z+3(z+2)=14+2z equation:


Simplifying
z + 3(z + 2) = 14 + 2z

Reorder the terms:
z + 3(2 + z) = 14 + 2z
z + (2 * 3 + z * 3) = 14 + 2z
z + (6 + 3z) = 14 + 2z

Reorder the terms:
6 + z + 3z = 14 + 2z

Combine like terms: z + 3z = 4z
6 + 4z = 14 + 2z

Solving
6 + 4z = 14 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
6 + 4z + -2z = 14 + 2z + -2z

Combine like terms: 4z + -2z = 2z
6 + 2z = 14 + 2z + -2z

Combine like terms: 2z + -2z = 0
6 + 2z = 14 + 0
6 + 2z = 14

Add '-6' to each side of the equation.
6 + -6 + 2z = 14 + -6

Combine like terms: 6 + -6 = 0
0 + 2z = 14 + -6
2z = 14 + -6

Combine like terms: 14 + -6 = 8
2z = 8

Divide each side by '2'.
z = 4

Simplifying
z = 4

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