z+3/2=5

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Solution for z+3/2=5 equation: 



z+3/2=5

We move all terms to the left:

z+3/2-(5)=0

determiningTheFunctionDomain
z-5+3/2=0

We multiply all the terms by the denominator


z*2+3-5*2=0

We add all the numbers together, and all the variables

z*2-7=0

Wy multiply elements

2z-7=0

We move all terms containing z to the left, all other terms to the right

2z=7

z=7/2

z=3+1/2

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