z+3/z-7=8/-3

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Solution for z+3/z-7=8/-3 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z+3/z-7 = 8/(-3) // - 8/(-3)

z+3/z-(8/(-3))-7 = 0

z+3/z+8/3-7 = 0

1*z^1+3*z^-1-13/3*z^0 = 0

(1*z^2-13/3*z^1+3*z^0)/(z^1) = 0 // * z^2

z^1*(1*z^2-13/3*z^1+3*z^0) = 0

z^1

z^2+(-13/3)*z+3 = 0

z^2+(-13/3)*z+3 = 0

DELTA = (-13/3)^2-(1*3*4)

DELTA = 61/9

DELTA > 0

z = ((61/9)^(1/2)-(-13/3))/(1*2) or z = (-(-13/3)-(61/9)^(1/2))/(1*2)

z = ((61/9)^(1/2)+13/3)/2 or z = (13/3-(61/9)^(1/2))/2

z in { (13/3-(61/9)^(1/2))/2, ((61/9)^(1/2)+13/3)/2} 

z in { (13/3-(61/9)^(1/2))/2, ((61/9)^(1/2)+13/3)/2 }

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